stpcpy -- copy a string returning a pointer to its end


#include <string.h>

char *stpcpy(char *dest, const char *src);


The stpcpy() function copies the string pointed to by src (including the terminating \0 character) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

Return Value

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null character) rather than the beginning.


For example, this program uses stpcpy to concatenate foo and bar to produce foobar, which it then prints.

#include <string.h>

int main (void) { char *to = buffer; to = stpcpy (to, "foo"); to = stpcpy (to, "bar"); printf ("%s\n", buffer); }